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Messages - AdrenalineXV

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1
Media / Re: Overtaking etiquette in AdrenalineX
« on: April 28, 2015, 05:40:28 pm »

2
Media / Overtaking etiquette in AdrenalineX
« on: April 28, 2015, 05:29:19 am »
Hi. Please watch this.

[youtube]http://www.youtube.com/watch?feature=player_detailpage&v=eebXtywMD9Y[/youtube]



Regards.

3
Media / Re: !! YOUR VIDEOS !!
« on: April 23, 2015, 06:45:36 pm »
It's me driving in NFSU_Mitsubishi_Eclipse :laugh:
TOP 1 by Tropkillaz

[youtube]http://www.youtube.com/watch?v=z5Kd6FSpJ_0&feature=youtu.be[/youtube]

Thanks a lot for BulleT.  ;)

I want those street mods. Are they allowed btw?

4
Off-Topic / Re: Post logical mathematical reasoning problems here.
« on: April 23, 2015, 06:08:03 am »
Anything multiplied by 10, 100 or 1000 is even and adding an even number to an odd/even number results in an odd/even number. Therefore only the last digit matters and every number will be odd except for those ending in 6, of which there are 3! = 6.
Ok mooman, I have got your point. Now: 7, 3, 5, 6. There are 3 odd numbers, that means that just 3 of four numbers can be used to get a four-digit odd number; so: 3 out of four numbers.

3 possibilities will be multiplied for the rest of available digits: 3*3*2*1 = odd numbers.

1 possibility will be multiplied in order to get the total of even numbers: 1*3*2*1 = even numbers.

Thanks.



5
Off-Topic / Re: Post logical mathematical reasoning problems here.
« on: April 23, 2015, 04:34:30 am »
I'm so confused.

mooman, Agus:

It is the same as above: If 24 numbers (four-digit each one) can be formed with: 7, 3, 5 ,6. Find the quantity of odd numbers from these.

Regards.

6
Off-Topic / Post logical mathematical reasoning problems here.
« on: April 23, 2015, 02:32:43 am »
Question 1:

With the digits 7, 3, 5, 6; 24 four-digit numbers can be formed. From these 24 numbers, the quantity of odd numbers is the same as a:

So, I know that 4! / (4-4)! = 24. There are 3 odd numbers and one even number. What is next?

Regards.


7
Off-Topic / Re: mooman, try to solve that
« on: April 15, 2015, 05:34:54 pm »
July 16.

It's not really difficult, but you just need to think logically for a longer period and that is hard for most people.
I do not get it yet. Btw, there must be a section named "Logical mathematical problems" and users have to put the number of the problem in the way "n+1"; being "n=1" for the first user to post the question. Regards.

8
Why don't you make a thread called "Help me with my maths homework" and just post all your questions there instead of making 100 threads lol.


It is not my homework, I do this because I want to pass the aptitude test in the university and I do not understand some exercises.
Regards.

9
The final challenge will be the count how many threads he made.
mooman: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
I do not get why you do those divisions; more than understanding n!

10
A: (1+1/2) * (1+1/3) * (1+1/4) ... (1+1/109)  = (2/2+1/2) * (3/3+1/3) * (4/4+1/4) ... (109/109+1/109) =
(3/2) * (4/3) * (5/4) ... (110/109) = (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
B: (1-1/2) * (1-1/3) * (1-1/4) ... (1-1/99) = (2/2-1/2) * (3/3-1/3) * (4/4-1/4) ... (109/109-1/109) =
(1/2) * (2/3) * (3/4) ... (108/109) = 108!/109! = 1/109
I do not understand this: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
Look at this I have found:




11
The answer has x in it but the questions don't lol, what
mooman, The questios are : A and B. This is to search with google: exp(-((x-4)^2+(y-4)^2)^2/1000) + exp(-((x+4)^2+(y+4)^2)^2/1000) + 0.1exp(-((x+4)^2+(y+4)^2)^2)+0.1exp(-((x -4)^2+(y-4)^2)^2)

So. What is the result of:

(1+1/2) * (1+1/3) * (1+1/4) ... (1+1/109)

What is the result of:

(1-1/2) * (1-1/3) * (1-1/4) ... (1-1/99)

Btw, do I have to do just a thread for the logical mathematical reasoning?
Regards.

12
 >:D     exp(-((x-4)^2+(y-4)^2)^2/1000) + exp(-((x+4)^2+(y+4)^2)^2/1000) + 0.1exp(-((x+4)^2+(y+4)^2)^2)+0.1exp(-((x -4)^2+(y-4)^2)^2)      >:D

El resultado de la siguiente multiplicación:
The result of the following multiplication:

A) (1+1/2) * (1+1/3) * (1+1/4) ... (1+1/109)

B) (1-1/2) * (1-1/3) * (1-1/4) ... (1-1/99)



Regards.
Saludos cordiales.

13
A perfect cube must have each of its factors repeated 3 times. It could also be written as (2*3)^3=6^3.

Ok, thank you. I will study this topic later to understand it the best.

14
18 is 2*3*3 so the lowest perfect cube containing it would be 2*2*2*3*3*3 = 216 meaning you have to multiply it by 2*2*3 = 12.
Thank you mooman, but I do not get it. I just understand 18 is 2*3*3, but why do you go to 2*2*2*3*3*3 = 216? Regards.

15
And we are at it again.

What is the lowest number that multiplied by 18 gives a perfect cube as a product?  Regards.

¿Cuál es el menor número que multiplicado por 18 da un cubo perfecto como un producto?  Saludos cordiales.


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