How about you just post your homework in ONE thread instead of spamming the forum with topics?
The answer has x in it but the questions don't lol, whatmooman, The questios are : A and B. This is to search with google: exp(-((x-4)^2+(y-4)^2)^2/1000) + exp(-((x+4)^2+(y+4)^2)^2/1000) + 0.1exp(-((x+4)^2+(y+4)^2)^2)+0.1exp(-((x -4)^2+(y-4)^2)^2)
A: (1+1/2) * (1+1/3) * (1+1/4) ... (1+1/109) = (2/2+1/2) * (3/3+1/3) * (4/4+1/4) ... (109/109+1/109) =I do not understand this: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
(3/2) * (4/3) * (5/4) ... (110/109) = (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
B: (1-1/2) * (1-1/3) * (1-1/4) ... (1-1/99) = (2/2-1/2) * (3/3-1/3) * (4/4-1/4) ... (109/109-1/109) =
(1/2) * (2/3) * (3/4) ... (108/109) = 108!/109! = 1/109
Why don't you make a thread called "Help me with my maths homework" and just post all your questions there instead of making 100 threads lol.(http://www.ultraimg.com/images/XC6zB.gif)
The final challenge will be the count how many threads he made.mooman: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
Why don't you make a thread called "Help me with my maths homework" and just post all your questions there instead of making 100 threads lol.(http://www.ultraimg.com/images/XC6zB.gif)
if you want 100*99*98*...*3*2*1 you write 100!. But if you want for example 100*99*98*...*13*12*11 you should write 100!/10!. I could've written 2 instead of 2! but I thought it was clearer lol. Because the numerators go from 3 to 110The final challenge will be the count how many threads he made.mooman: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
I do not get why you do those divisions; more than understanding n!