1
This section allows you to view all posts made by this member. Note that you can only see posts made in areas you currently have access to.
It's me driving in NFSU_Mitsubishi_Eclipse
TOP 1 by Tropkillaz
[youtube]http://www.youtube.com/watch?v=z5Kd6FSpJ_0&feature=youtu.be[/youtube]
Thanks a lot for BulleT.
Anything multiplied by 10, 100 or 1000 is even and adding an even number to an odd/even number results in an odd/even number. Therefore only the last digit matters and every number will be odd except for those ending in 6, of which there are 3! = 6.Ok mooman, I have got your point. Now: 7, 3, 5, 6. There are 3 odd numbers, that means that just 3 of four numbers can be used to get a four-digit odd number; so: 3 out of four numbers.
I'm so confused.
July 16.I do not get it yet. Btw, there must be a section named "Logical mathematical problems" and users have to put the number of the problem in the way "n+1"; being "n=1" for the first user to post the question. Regards.
It's not really difficult, but you just need to think logically for a longer period and that is hard for most people.
Why don't you make a thread called "Help me with my maths homework" and just post all your questions there instead of making 100 threads lol.
The final challenge will be the count how many threads he made.mooman: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
A: (1+1/2) * (1+1/3) * (1+1/4) ... (1+1/109) = (2/2+1/2) * (3/3+1/3) * (4/4+1/4) ... (109/109+1/109) =I do not understand this: (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
(3/2) * (4/3) * (5/4) ... (110/109) = (110!/2!)/109!= 110!/(109!*2!) = 110/2 = 55
B: (1-1/2) * (1-1/3) * (1-1/4) ... (1-1/99) = (2/2-1/2) * (3/3-1/3) * (4/4-1/4) ... (109/109-1/109) =
(1/2) * (2/3) * (3/4) ... (108/109) = 108!/109! = 1/109
The answer has x in it but the questions don't lol, whatmooman, The questios are : A and B. This is to search with google: exp(-((x-4)^2+(y-4)^2)^2/1000) + exp(-((x+4)^2+(y+4)^2)^2/1000) + 0.1exp(-((x+4)^2+(y+4)^2)^2)+0.1exp(-((x -4)^2+(y-4)^2)^2)
A perfect cube must have each of its factors repeated 3 times. It could also be written as (2*3)^3=6^3.
18 is 2*3*3 so the lowest perfect cube containing it would be 2*2*2*3*3*3 = 216 meaning you have to multiply it by 2*2*3 = 12.Thank you mooman, but I do not get it. I just understand 18 is 2*3*3, but why do you go to 2*2*2*3*3*3 = 216? Regards.