Topic: Which one is correct?

[[FSR]adan]

Other example:

2(1+2) = 2x1 = 2 , + 2x2 = 4 , 4 + 2 = 6 --> 6:6 = 1 !

2(1+2) = 2 x 3 = 6 --> 6:6 = 1 !

you cannot multiply like that, you must consider 6/2 (=3) as single number (e.g. 6/2=9/3=12/4=3)
6/2(2+1)=3(2+1)=6+3 or 3*3=9

[[LSR]Cassidy]

Well im just saying that you can also do it like this:

[2(1+2)] = 2x1 + 2x2 = 6 --> 6:6 = 1.

Because there is an X between 2 and (1+2) = 2 x (1+2)


Meh, i searched on the internet, and i now think its 9 too...

[[FSR]Ush]

Why are you all this obsessed with maths.. really something is wrong with you guys.

[[LSR]Ride]

9

[[MAF]Snoopy]

u know nothing about algebra...

Then explain

[[MAF]Epoxi]

I doesn't matter which one is correct, just stop entering calculations into the calculator in such an ambiguous way. 

[[MAF]Aj_Lajk_Bir]

Why are you all this obsessed with maths.. really something is wrong with you guys.

^!!!!!!!

[Gen]

Nah, nothing wrong with us. Everyone enjoys a small intellectual task every once in a while.

[[FSR]Ush]

You should challenge yourself more through the day

[Gen]

I got plenty of other stuff to challenge myself with

[[AK47]M4lysz]

1 is correct

calculators should count it like this: = 1

the calculators in the first picture is wrong

this would be like  6/(2(1+2))

[[FSR]adan]

a = x
a + a = a + x
2a = a + x
2a - 2x = a + x - 2x
2(a - x) = a + x - 2x
2(a - x) = a - x
2 = 1

problems, mathematicians? :7

[[AK47]M4lysz]

that does not say 2=1
it say a=x so when x = a we can swap one for another and don`t use them both
2(a-a)= 0 = a-a
so your unknown can be any number

[[MAF]mooman]

a = x
a + a = a + x
2a = a + x
2a - 2x = a + x - 2x
2(a - x) = a + x - 2x
2(a - x) = a - x
2 = 1

problems, mathematicians? :7

division by 0 on last line


the answer to the first question is 9 because you do multiplication before division

[[MAF]Snoopy]

mooman has spoken. case closed.