Topic: Which one is correct?

[[FSR]Ali]

[MadMax]

i bet 9 is correct

6/2(1+2)

1st do (1+2) so is 3

then
6/2*3
6/2=3 and 3*3 = 9

[[MAF]Karlis]

1st one, once () is done, its divisions order.
seems like they have different settings tho.

[[MAF]Cthulhu]

1 is correct

calculators should count it like this: = 1

the calculators in the first picture is wrong

[[MAF]Agus]

But if you think 6/2 as a fraction and then that fraction x (2+1), the result would be 9

[FSR|BuRNZ]

definitely left one

[[AK47]M4lysz]

definitely left one

[some_punk]

u know nothing about algebra...

[[FSR]Ali]

That's how i see it...
6/2(1+2)=
6/2= 3
3(1+2)= 3+6 = 9 ...

[[MAF]Karlis]

1 is correct

calculators should count it like this: = 1

the calculators in the first picture is wrong

nah x equals to (x)/(y), not x/y, therefore this cant be converted.
       y
and calculators don't do them like that, they do it strongly sequential, meaning it will never put () if its not specified/needed.

don't forget that if priorities are equal(which is the case with division and mul), there's mathematical law to take leftmost expression first.

[[LSR]Cassidy]

1 is correct

It is definitely 1! Dont think its 9, that is just a lie!

Other example:

2(1+2) = 2x1 = 2 , + 2x2 = 4 , 4 + 2 = 6 --> 6:6 = 1 !

2(1+2) = 2 x 3 = 6 --> 6:6 = 1 !

[[MAF]Karlis]

youre forgetting that 2(1+2) is the same as 2*(1+3) the lack of * doesn't change any of the orders.

[MadMax]

2(1+2) = 2x1 = 2 , + 2x2 = 4

w00t??
6/2(1+2)=9!
1st you do in brackets
(1+2)=3
then 2(1+2) = 2*3
6/2*3
6/2=3
3*3=9

[[FSR]adan]

i bet 9 is correct

6/2(1+2)

1st do (1+2) so is 3

then
6/2*3
6/2=3 and 3*3 = 9

[[MAF]Aj_Lajk_Bir]

damn maths! fuck you!